129.168.31.2/27
a. subnetmask
b. network adress
c. broadcast address
d. Jumlah host & subnet
e. Range IP
Jawab:
a./27 = angka 1 disemua oktet
biner : 11111111.11111111.1111111.11100000
desimal : 255.255.255.224
b.
NetID:
IP (biner)
netmask (biner)
------------------ and
Disini menggunakan logika AND yaitu:
And
0 ketemu 0 = 0
1 ketemu 1 = 1
0 ketemu 1 = 0
1 ketemu 0 = 0
10000001.10101000.00011111.00000010
11111111.11111111.11111111.11100000
---------------------------------------------- AND
10000001.10101000.00011111.00000000